Question 1043017
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Jose is 3 times as old as Wally. Five years from now, The sum of their ages is 42. How old are they now?
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<pre>
Let J = Jose's age now; W = Wally's age now. Then

J = 3W,               (1)     ( "Jose is 3 times as old as Wally" )
(J+5) + (W+5) = 42.   (2)     ( "Five years from now, The sum of their ages is 42" )

Simplify 2):

J + W + 10 = 42,   or

J + W = 42-10 = 32.

Now substitute J= 3W from (1) into the last equation. You will have

3W + W = 32.

Can you complete the solution from this point?
</pre>

There is a bunch of lessons with solved age problems in this site

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Age-problems-and-their-solutions.lesson>Age problems and their solutions</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Fresh-formulation-of-a-traditional-age-problem.lesson>A fresh formulation of a traditional age problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=http://www.algebra.com/algebra/homework/word/age/Really-intricate-age-word-problem.lesson>Really intricate age word problem</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/Selected-age-word-problems-from-the-archive.lesson>Selected age word problems from the archive</A>

&nbsp;&nbsp;&nbsp;&nbsp;- <A HREF=https://www.algebra.com/algebra/homework/word/age/04-OVERVIEW-of-lessons-on-age-problems.lesson>OVERVIEW of lessons on age problems</A>


They were developed to teach you on solving these problems.


Read them and become an expert in this area.