Question 1042893
Use Cramer's rule,
{{{A=(matrix(3,3,
4,6,-1,
2,1,3,
1,-2,2))}}}
{{{abs(A)=31}}}
.
.
.
{{{A[p]=(matrix(3,3,
0,6,-1,
4,1,3,
10,-2,2))}}}
{{{abs(A[p])=150}}}
.
.
.
{{{A[q]=(matrix(3,3,
4,0,-1,
2,4,3,
1,10,2))}}}
{{{abs(A[q])=-104}}}
.
.
.
{{{A[r]=(matrix(3,3,
4,6,0,
2,1,4,
1,-2,10))}}}
{{{abs(A[r])=-24}}}
.
.
.
So then,
{{{p=abs(A[p])/abs(A)=150/31}}}
{{{q=abs(A[p])/abs(A)=-104/31}}}
{{{r=abs(A[p])/abs(A)=-24/31}}}