Question 1042887
{{{A=B/2-3}}}
{{{A*B=540}}}
Substituting,
{{{(B/2-3)B=540}}}
{{{B^2/2-3B=540}}}
{{{B^2-6B-1080=0}}}
{{{(B-36)(B+30)=0}}}
Two solutions,
{{{B-36=0}}}
{{{B=36}}}
Then,
{{{A=36/2-3}}}
{{{A=18-3}}}
{{{A=15}}}
and
{{{B+30=0}}}
{{{B=-30}}}
Then,
{{{B=-30/2-3}}}
{{{B=-15-3}}}
{{{B=-18}}}