Question 1042813
The cost of a can of Coca-Cola on January 1, 1960 , was 10 cents. The function C(t)=0.10e^(0.0576t) gives the cost of a can of Coca-Cola, C(t), t years after that.

a.) How much does a can of Coca Cola cost in 1975 (round to nearest penny)?
# of years 60 to 75 = 15
C(15) = 0.10*e^(0.0576*15) = 0.10*2.3726 = 0.237 = 24 cents if rounded up
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b.) In what year will a can of Coca-Cola cost $1.00 (round to nearest whole year).
Solve for "t"
1 = 0.10*e^(0.0576t)
e^(0.0576t) = 10
Take the natural log of both sides to get:
0.0576t = 2.3026
t = 40 if rounded up
Ans: 1960 + 40 = year 2000
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c.) How much does a can of Coca-Cola cost in 2045 ?
1960 to 2045 = 85 years
C(85) = 0.10*e^(0.0576*85)
I'll leave that calculation to you.
Cheers
Stan H.
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