Question 90614
let P(x) equal profit ... P(x)=R(x)-C(x) ... P(x)=-0.3x^2+200x-(80x+9400) ... P(x)=-0.3x^2+120x-9400


the maximum lies on the axis of symmetry of the graph and is defined by x=-b/2a


in this case, x=-120/(2(-0.3)) ... x=200