Question 1042723
 Find the confidence interval specified. 
The mean score,x , on an aptitude test for a random sample of 5 students was 73. Assuming that σ=15 construct a 95.44% confidence interval for the mean score, μ of all students taking the test. 
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(1-0.9544)/2 = 0.0228
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-invNorm(0.0228) = 1.9991
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x-bar = 73
ME = z*s/sqrt(n) = 1.9991*(15/sqrt(73) = 3.51
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95.44% CI:: 73-3.51 < u < 73+3.51
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Cheers,
Stan H.
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