<PRE><B>Question 1042685</B>
A small motorboat travels 13 mph in still water. It takes 2 hours longer to travel 60 miles going upstream than it does going downstream. Find the rate of the current.
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I am at a point where I have: 
60/(13-x) - 60/(13+x) =2 
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60(13+x) - 60(13-x) = 2(169-x^2)
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120x = 2*169 - 2x^2
2x^2+120x-2*169 = 0
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x^2 + 60x - 169 = 0
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x = [-60 +- sqrt(3600-4*-169)]/(2)
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Positive solution::
x = 2.32 mph
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Cheers,
Stan H.
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