Question 1042680
 explain the steps in converting standard form to vertex form 
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y = ax^2 + bx + c
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Factor out "a" to get::
y = a(x^2 + (b/a)x) + ? + c
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Complete the square and maintain the equality of the sides::
y = a(x^2 + (b/a)x + (b/2a)^2) + c - a(b/2a)^2
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Factor to get::
y = a(x+(b/2a))^2 + c - (b^2/4a)
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Simply::
y = a(x+(b/2a))^2 + [4ac-b^2]/(4a)
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Rearrange::
y = a(x+(b/2a))^2 - [b^2-4ac]/(4a)
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Cheers,
Stan H.