Question 1042661
Use the general equation of a circle centered at (x,0) and use the two points.
{{{(x-0)^2+(0-4)^2=R^2}}}
{{{x^2+16=R^2}}}
and
{{{(x-1)^2+(0-3)^2=R^2}}}
{{{(x-1)^2+9=R^2}}}
Set them equal to each other,
{{{x^2+16=(x-1)^2+9}}}
{{{x^2+16=x^2-2x+1+9}}}
{{{-2x+10=16}}}
{{{-2x=6}}}
{{{x=-3}}}
Then solve for R,
{{{(-3)^2+16=R^2}}}
{{{R^2=9+16}}}
{{{R^2=25}}}
{{{R=5}}}
.
.
.
*[illustration lp8.JPG].