Question 1042648
Rewrite the equation of the line as 4x + y +30 = 0.

===> The distance of the center (-4,3) of the circle from the tangential line 
4x + y +30 = 0 is given by {{{d = abs(4*-4+3+30)/sqrt(4^2+1^2) = 17/sqrt(17) = sqrt(17)}}}, which, incidentally, is also the radius of the circle.

===> the standard equation of circle is {{{(x+4)^2+(x-3)^2 = (sqrt(17))^2}}}, or
 {{{(x+4)^2+(x-3)^2 = 17}}}.