Question 1042638
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No.  Not possible.  Since the total amount of money ends in a 0, it is not possible to have an odd number of quarters.  So you have an even number of quarters.  If you had 12 quarters, you would have $3.00, which is too much, so the most quarters you could have is 10 quarters, making $2.50, and then you would have 3 dimes to make the additional $0.30 necessary to make the $2.80.  10 is only 7 more than 3, so this combination does not provide a solution where you have 8 more quarters than dimes.  If you have 8 quarters making $2.00, you would have 8 dimes also, not a solution.  If you have 6 or fewer quarters, it is impossible to have 8 more quarters than dimes.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
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