Question 1042620
.
f(x)= {{{x^3-5x^2-25x+125}}} = 


= {{{(x^3 - 5x^2) - 25(x-5)}}} = {{{x^2(x-5) - 25(x-5)}}} = {{{(x^2-25)*(x-5)}}} = (x-5)*(x+5)*(x-5) = {{{(x-5)^2*(x+5)}}}.


The roots are: 5 of multiplicity 2 and -5 of multiplicity 1.


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{{{graph( 330, 330, -10.5, 10.5, -10.5, 150.5,
          x^3-5x^2-25x+125
)}}}


<B>Figure</B>. Plot f(t) = {{{x^3-5x^2-25x+125}}}

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