Question 13096
{{{(3-2/(n-4))/(5+4/(n-4))}}}={{{((3*(n-4)-2)/(n-4))/((5*(n-4)+4)/(n-4))}}}={{{((3*n-3*4-2)/(n-4))/((5*n-5*4+4)/(n-4))}}}={{{((3n-12-2)/(n-4))/((5n-20+4)/(n-4))}}}={{{((3n-14)/(n-4))/((5n-16)/(n-4))}}}={{{((3n-14)/(n-4))*((n-4)/(5n-16))}}}={{{(3n-14)/(5n-16)}}}

OK