<PRE><B>Question 1042457</B>
Let {{{ d }}} = distance in miles traveled the first 2 hrs
{{{ d = 10*2 }}}
{{{ d = 20 }}} mi
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The rest of the way is:
{{{ 60 - 20 = 40 }}} mi
{{{ 40 = 30*t }}}
{{{ t = 4/3 }}} hrs
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His total time doing it this way is:
{{{ 2 + 4/3 = 10/3 }}} hrs
( or 3 hrs and 20 min )
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20 mi/hr the whole way:
{{{ 60 = 20*t }}}
{{{ t = 3 }}} hrs
It is quicker to go 20 mi/hr the whole way</PRE>