Question 1042400
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What you describe is impossible.  If two balls have A and C on them and five balls have only C, then all 7 Cs are accounted for.  Also, two of the five As are accounted for, leaving three As.  If two balls have only a B on them, that leaves 8 Bs that must be paired with As since all of the Cs are used, but there are only three As.  Impossible.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
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