Question 1042354
First we calculate how many committees of 2 women we can make out of the 5 women:

{{{W = 5!/(5-2)!2! = 10}}} hence we can have 10 such committees
Similarly, we calculate the number of committees of 3 out of 6 men:
{{{M = 6!/(6-3)!3! = 20}}}
Now we must combine each of the first 10 women committees with each of the 20 men committees; thus the total number must be {{{10*20=200}}}