Question 1042192

Andrew has two children, David and Helen. The sum of their three ages is 49. David’s age is three times that of Helen. In 5 years time, Andrew’s age will be three times David’s age. What is the product of their ages now?
<pre>Let Helen's age be H, and Andrew's, A
Then David's is: 3H
We also get: A + 5 = 3(3H + 5)
A + 5 = 9H + 15
A = 9H + 10 
Since their ages sum to 49, then we get: H + 3H + 9H + 10 = 49
13H = 49 - 10
13H = 39
H, or Helen's age = {{{39/13}}}, or 3
David's age: 3(3), or 9
Andrew's age: 49 - (3 + 9), or 49 - 12, or 37

Product of their ages: 3(9)(37). Do you think you can find this?