Question 1042194
Identify the simplest common denominator.
{{{system(2x,5)}}},alltogether, {{{2*5*x}}}.


{{{2*5*x(1/(2x)-3)=2*5*x(x/5)}}}


{{{5-2*3*5*x=2x^2}}}


{{{5-30x=2x^2}}}


{{{-2x^2-30x+5=0}}}
and note, also one more step for better convenience, 
{{{(-1)(-2x^2-30x+5)=-1*0}}}


{{{2x^2+30x-5=0}}}


Either this is factorable or it is not factorable.  If factorable, you already learned what to do.  If NOT factorable, then you can solve using the formula for general solution of quadratic formula.



--
Discriminant, {{{(30)^2-4*2*(-5)=900+40=940}}}
-
{{{940=94*2*5=2*47*2*5=2^2*5*47}}}
--
--
{{{x=(-30+- sqrt(2^2*5*47))/(2*2)}}}


{{{x=(-30+- 2*sqrt(235))/(2*2)}}}


{{{highlight(x=(-15+- sqrt(235))/2)}}}