Question 1042176
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  P(t)\ =\ 10(1.05)^t]


Note 2015 is represented by *[tex \Large t\ =\ 2015\ -\ 2010\ =\ 5]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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