Question 1042171
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Replace *[tex \Large h(x)] with *[tex \Large y]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ 3x\ -\ 2]


Solve for *[tex \Large x] in terms of *[tex \Large y]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  x\ =\ \frac{y\ +\ 2}{3}]


Swap the variables (put *[tex \Large x] where *[tex \Large y] is and put *[tex \Large y] where *[tex \Large x] is).



*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ \frac{x\ +\ 2}{3}]  


Replace *[tex \Large y] with *[tex \Large h^{-1}(x)]


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  h^{-1}(x)\ =\ \frac{x\ +\ 2}{3}] 


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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