Question 1042100
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<i>There are 8 nickels and 8+9=17 dimes.</i>
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What are you trying to answer in that?




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<i>A collection of dimes and quarters has a total value of $2.20. If there are three times as many quarters, how many of each coin is in the equation?</i>
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Count of dimes is d.
Count of quarterss is q.
System of equations for account of the money and of the coins is this:
{{{system(0.1d+0.25q=2.20,q=3d)}}}


Simplify the money account equation.
{{{10d+25q=220}}}
{{{2d+5q=22*2*5/5}}}
{{{2d+5q=44}}}
and substitute using the other equation, for q.
{{{2d+5*3d=44}}}
and solve first for d.
{{{highlight_green(17d=44)}}}-------this is bad because it will not give a whole numbered value for d, and the solution quantity of coins must be whole numbered values for each.


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