Question 1042090
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Take the square root of 5607 to get 
{{{sqrt(5607)=74.8799}}}
So 5607 is between {{{74^2=5476}}} and {{{75^2=5625}}}


We must ask ourselves: what is the value of x that makes this equation true?

5607+x = 5625


To find out, subtract 5607 from both sides to get


5607+x = 5625
5607+x-5607 = 5625-5607
x = 18

Therefore, you must add 18 to 5607 to get the sum to be a perfect square. 18 is the smallest you can add.


Final Answer: <font color=red>18</font>
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