Question 1042083
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I'm assuming the two functions given to you are


{{{f(x) = 1/x + 3x}}}


{{{g(x) = -1/x + 6x-4}}}



If that's the case, then...



{{{f(x) + g(x) = (f(x)) + (g(x))}}}



{{{f(x) + g(x) = (1/x + 3x) + (-1/x + 6x-4)}}}



{{{f(x) + g(x) = 1/x + 3x + -1/x + 6x-4}}}



{{{f(x) + g(x) = (1/x-1/x) + (3x + 6x)-4}}}



{{{f(x) + g(x) = (1-1)/x + 9x-4}}}



{{{f(x) + g(x) = 0/x + 9x-4}}}



{{{f(x) + g(x) = 0 + 9x-4}}}



{{{f(x) + g(x) = 9x-4}}}



where {{{x<>0}}}
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