Question 1041846
 {{{(A*logA*10^(log(B/A^3)+3logA) )/(-B*log(1/A))}}}

= {{{(A*logA*10^(log(B/A^3) + logA^3) )/(-B*log(1/A))}}}

= {{{(A*logA*10^(log((B/A^3)*A^3)) )/(B*logA)}}}

= {{{(A*logA*10^(logB))/(B*logA)}}}

= {{{(A*logA*B)/(B*logA)}}}

= A