<PRE><B>Question 1041785</B>
The boys of a school can be arranged in 12,15 and 18 equal rows and also
into a solid square.
 What is the least number of boys that the school can have? 
:
find the least common multiple of 12, 15 and 18, use prime factoring
12: 2*2*3
15: 3*5
18: 2*3*3
therefore
2*2*3*3*5 = 180 but not a perfect square
find a multiple of 180 that is a perfect square,
That would be 3600 boys
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