Question 1041794
If there is 80 cows and hens and the legs are 208 how many cows and hens
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animals:: c + h = 80
legs:::  4c + 2h = 208
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Modify for  elimination::
c + h = 80
2c+ h = 104
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Subtract and solve for "c"::
c = 24 (# of cows)
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Solve for "h"::
h = 80-c = 80-24 = 56 (# of hens)
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Cheers,
Stan H.
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