Question 1041751
Simply substitute for y.  Solve the resulting equation in x...


{{{6x-x^2-5=3}}}
{{{-x^2+6x-8=0}}}

{{{x^2-6x+8=0}}}

{{{(x-2)(x-4)=0}}}



{{{system(x=2,or,x=4)}}}-----and then find the corresponding y value for each of them.