Question 90475
Problem:
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{{{sqrt(x+4) =3}}}
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solve for x.
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Begin by squaring both sides. When you do that the equation becomes:
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{{{(sqrt(x+4))^2 = 3^2}}}
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which after squaring becomes:
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{{{x + 4 = 9}}}
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solve for x by subtracting 4 from both sides to get:
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{{{x = 9 - 4 = 5}}}
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The solution, therefore, is {{{x = 5}}}
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Check by substituting 12 for x in the original equation:
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{{{(sqrt(5 + 4)) = 3}}}
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Add the terms in the parentheses:
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{{{sqrt(9) = 3}}}
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The square root of 9 results in +3, so the equation is true and the answer x = 5 works.
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