Question 1041682
Let the two consecutive integers be n and n+1. Then:
n(n+1)=4(n+n+1)-16
n²+n=8n-12
n²-7n+12=0
(n-4)(n-3)=0
n=4,3
The two consecutive integers are 3 and 4. &#9786;&#9786;&#9786;&#9786;