Question 1041645
{{{(X+Y+Z)/3=2200}}}
{{{X+Y+Z=6600}}}
.
.
{{{X=2Y}}}
{{{X=3Z}}}
So then,
{{{Y=X/2}}}
and
{{{Z=X/3}}}
Substituting,
{{{X+X/2+X/3=6600}}}
{{{(6/6)X+(3/6)X+(2/6)X=6600}}}
{{{(11/6)X=6600}}}
{{{X=3600}}} <--- Peter
Then,
{{{Y=3600/2=1800}}} <--- James
{{{Z=3600/3=1200}}} <--- John