Question 90332


    Find an equation for the line with y-intercept 3 that is perpendicular to the line y=2/3x-4.

     Let the required eq'n be y = mx+c

if the y- intercept is 3 then c= 3

To find the slope , the two lines are perpendicular  hence product of their 

  slopes  = -1. In the given eq'n slope M = 2/3
  
   slope of the required line = m = ?

                     m*M = -1   or m = -1/M = -1/2/3 = -3/2

   substituting the values of m and c we get 

                    y = (-3/2)x+3 is the solution.