Question 90454


     solve by substitution method: 
x=y+3
3x-2y=4
          x = y+3..........(1)

       3x-2y = 4...........(2)

    substituting for x from eq'n (1)  in eq'n (2)  we get
    
    3(y+3)-2y = 4

    3y+9-2y = 4

         y = -9+4 = -5

  substitute for y in eq'n(1) we get x = -5+3 = -2

    The solution for the given eq'ns is x = -2   and y = -5