Question 1041495
Examine a cross section, having vertex imagined as a minimum if on a cartesian system.  A point is ( 12/2, 4.5 ).  TThe vertex at the origin.  Recall, this is a parabola.


(1)
Change information into standard form equation for the parabola.


(2)
Find how far p, is the focus from the vertex, based on the typical model derived equation,  {{{4py=(x-0)^2}}};  this may require some care, but otherwise not too difficult.




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Parabola with vertex as minimum, symmetry axis parallel to the y-axis, {{{y=a(x-h)^2+k}}} as standard form; vertex is  (h,k).
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Using given focus and directrix to derive an equation for a parabola having symmetry axis parallel to the y-axis will be of a form  {{{4p(y-k)=(x-h)^2}}}, and the value p is how far the focus is from the vertex.  Look at and study your lesson on this.