Question 90455



    solve by addition method:
x/3-y/2=-5/6
x/5-y/3=-3/5
 
  x/3-y/2 = -5/6   l.c.m for 2,3 = 6  multiply each term by 6 we get 
  2x-3y = -5......(1)

   x/5-y/3 =-3/5    l.c.m for 3,5 = 15  multiply each term by 15 we get 

  3x-5y =-9........(2)

    -3(2x-3y = -5)    (multiply eq'n (1) by -3)

     -6x+9y = 15......(3)

    2(3x-5y=-9)     (multiply  eq'n (2) by 2)

    6x-10y  = -18.....(4)

 adding eq'n(3)  and eq'n (4) we get -y =-3  or y =3

 substitute the value of y in eq'n(3) -6x+9*3 = 15

                -6x+27-15 = 0

                   12 = 6x or x = 12/6 = 2

  The required solution is x = 2  and y = 3