Question 1041563
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*[tex \LARGE \ \ \ \ \ \ \ \ \ \  FV\ =\ P\left(1\ +\ \frac{r}{n}\right)^{nt}]


Where *[tex \Large FV] is the future value, *[tex \Large P] is the principal invested, *[tex \Large r] is the interest rate expressed as a decimal, *[tex \Large n] is the number of compounding periods per year, and *[tex \Large t] is the number of years.


The amount of interest earned after year 5 depends a great deal upon the amount of time that has passed after year 5.  If you are talking about the 6th year, then you need to calculate the future value at the end of the 5th year using the formula above.  Then the amount of interest earned in the 6th year is 5% of the Future Value at the end of the 5th year.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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