<PRE><B>Question 1041526</B>
If the point (x,3) is equidistant from (3,-2) and (7,4), find the value of x.
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There&#39;s more than 1 way to do this.
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Label the points: A(3,-2), B(7,4)
Find the perpendicular bisector of AB.  The point will be on the bisector.
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Using distance formula:
d^2 = (x-3)^2 + (3+2)^2 distance^2 from A
d^2 = (x-7)^2 + (3-4)^2 distance^2 from B
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(x-3)^2 + (3+2)^2 = (x-7)^2 + (3-4)^2
{{{x^2 - 6x + 9 + 25 = x^2 - 14x + 49 + 1}}}
Solve for x
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