Question 1041504
The circle passes through the points (-4,8),(4,-4), and(3,-9).
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You didn't say what you want to do.
If you want to find the equation of the circle:
Label the points A(-4,8), B(4,-4), and C(3,-9).
Find the perpendicular bisector of AB and of BC.
Find the intersection of the 2 bisectors, that's the center of the circle (h,k).
The distance from the center to any point is the radius.
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{{{(x-h)^2 + (y-k)^2 = r^2}}}
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That's one way to do it.
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I prefer to use a matrix.
<pre>
| x^2+y^2    x    y   1|
|x1^2+y1^2  x1   y1   1|
|x2^2+y2^2  x2   y2   1|  = 0
|x3^2+y3^2  x3   y3   1|
</pre>