Question 1041377
<pre>Let y = the expression

{{{y=(x^2-3x+1)/(2x^2-3x+2)}}}

Show that the denominator is never 0.

Show that it has derivative

{{{(dy)/(dx)=(3(x^2-1))/(2x^2-3x+2)^2}}}

Set that = 0 and show that it has relative 
and absolute max at (-1,5/7) and an absolute
minimum at (1,-1).

Edwin</pre>