Question 1041286
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{{{f(x)=3x^3-2x^2+cx}}}
{{{f(x)=x*(3x^2-2x+c)}}} Factor out the GCF x
{{{0=x*(3x^2-2x+c)}}} Replace f(x) with 0
{{{x*(3x^2-2x+c)=0}}} Flip the equation



Since {{{x*(3x^2-2x+c)=0}}}, this means that {{{x = 0}}} or {{{3x^2-2x+c}}}


Since one root is {{{x = 0}}}, this means that one x-intercept is the ordered pair (x,y) = (0,0)


The only thing that comes close to that is (p,0) which is listed above. 


(p,0) = (0,0)
means p = 0


So the final answer is <font color=red size=4>choice D) 0</font>
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