Question 1041255

two numbers are in ratio 4:5. if difference of their cubes is 61, find the number
<pre>Let multiplicative factor be x
Then numbers are: 4x and 5x
Since the difference of their cubes is 61, we can say that: {{{(5x)^3 - (4x)^3 = 61}}}
{{{125x^3 - 64x^3 = 61}}}
{{{61x^3 = 61}}}
{{{x^3 = 61/61}}}______{{{x^3 = 1}}}_____x = 1
Therefore numbers are: {{{highlight_green(matrix(1,7, 4(1), or, 4, and, 5(1), or, 5))}}}