Question 1041115
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The number of "obtuse" varied directly as the number of "acute". 
If 2,400 were obtuse when 960 were acute, how many were acute when only 10 were obtuse? 
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<pre>
The proportion is  {{{2400/960}}} = {{{10/x}}},


where  "x" is = "how many were acute when only 10 were obtuse? ".

Solve for x:  x = {{{(960*10)/2400}}} = 4.

<U>Answer</U>.  4.
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