Question 1041122
From eq. 2,
{{{x=8y-6}}}
Substitute into eq. 1,
{{{(8y-6)y=9}}}
{{{8y^2-6y-9=0}}}
{{{(2y-3)(4y+3)=0}}}
Two solutions:
{{{2y-3=0}}}
{{{2y=3}}}
{{{y=3/2}}}
Then,
{{{x(3/2)=9}}}
{{{x=6}}}
and
{{{4y+3=0}}}
{{{4y=-3}}}
{{{y=-3/4}}}
Then,
{{{x(-3/4)=9}}}
{{{x=-12}}}
.
.
.
*[illustration dfc21.JPG].