Question 1041079
The area of a rectangle is 32cm^2. The width of the rectangle is 4 cm more than 3 times the length. 
What is the length of the rectangle is cm? 
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Equations:
W = 3L + 4
W*L = 32 cm^2
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Substitute for "W" and solve for "L"::
L(3L+4) = 32
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3L^2 + 4L - 32 = 0
Factor::
(3L-8)(L+4) = 0
Positive solution:
L = 8/3 = 2.6666.. cm
Solve for "W:
W = 3(8/3)+4 = 12 cm
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Cheers,
Stan H.
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