<PRE><B>Question 1041076</B>
The area of a rectangle in 48 in^2. It has w width that is 16 inches less than 4 times its length. 
What is the length of the rectangle? 
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Length = L 
Width = 4L-16
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Equation:
L(4L-16) = 48 in^2
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4L^2 - 16L - 48 = 0
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L^2 - 4L - 12 = 0
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Factor::
(L-6)(L+2) = 0
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Positive solution::
Length = 6 inches
Width = 4L-16 = 24-16 = 8 inches
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Cheers,
Stan H.
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