Question 1041019
<pre>
You can see this is very very unlikely.

If an event is repeated n times with a probability of success 
each time is p, then the probability of getting exactly x 
successes is given by the binomial formula:

{{{(nCx)p^x*(1-p)^(n-x)}}}

You case is n=6 trials (rolls)
The probability of a success (four) each time is p=1/6  
The number of successes x=5

{{{(6C5)(1/6)^5*(1-1/6)^(6-5)}}}

{{{(6)(1/6^5)*(5/6)^(1)}}}

{{{(6)(1/7776)*(5/6)}}}


{{{(cross(6))(1/7776)*(5/cross(6))}}}

{{{5/7776}}}

Edwin</pre>