Question 1040925
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The length of one leg of a right triangle is 8 ft. The length of the hypotenuse is 4 feet longer than the other leg. 
Find the length of the hypotenuse and the other leg
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{{{8^2 + x^2}}} = {{{(x+4)^2}}}   is the Pythagorean equation in this case.

{{{64 + x^2}}} = {{{x^2 + 8x + 16}}},

64 - 16 = 8x,

8x = 48,

x = 6 cm.

<U>Answer</U>.  The legs are 8 and 6 cm. The hypotenuse is 10 cm. (Classic (3-4-5) triangle)
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