Question 1040905
The ratio of Andrew's hourly wage to Bob's hourly wage is 2:3.
let x = the 1st multiplier
then
2x = A's hourly wage
and
3x = B's hourly wage
 The ratio of Bob's hourly wage to Chuck's hourly wage is 9.4.
let y = the 2nd multiplier
then
9y = B's hourly wage
4y = C's hourly wage
now we know
3x = 9y
therefore
x = 3y

 Andrew earned $600 last week and worked twice as many hours as Chuck,
let c = amt of $ earned by C
A's hrs = twice C's hrs
{{{600/(2x)}}} = 2({{{c/(4y)}}})
Replace x with 3y
{{{600/2(3y)}}} = 2({{{c/(4y)}}})
{{{600/(6y)}}} = {{{2c/(4y)}}}
multiply both sides by y
{{{600/6}}} = {{{2c/4}}}
100 = {{{c/2}}}
c = 2*100
c = $200 earned by C
:
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I'm not totally sure about this one, if I screwed it up, let me know in the comment. CK