Question 1040893
Let c=cheese pizza, p=pepperoni pizza, and s=supreme pizza. Then
c+p+s=32
7c+10p+13s=314
10p=2(7c);10p=14c
10c+10p+10s=320
7c+10p+13s=314
3c-3s=6;
7c+14c+13s=314
21c+13s=314
21c-21s=42
Subtracting the last equation from the second-to-last, we get
34s=272
s=8 supreme pizzas
p=14 pepperoni pizzas
c=10 cheese pizzas ☺☺☺☺