Question 1040857
Multiply both sides by {{{3x}}}.
{{{x^2+36=3x^2-6x}}}
{{{2x^2-6x-36=0}}}
{{{x^2-3x-18=0}}}
{{{(x-6)(x+3)=0}}}
So there are two solutions,
{{{x-6=0}}}
{{{x=6}}}
and
{{{x+3=0}}}
{{{x=-3}}}