Question 1040842
Let the integer be x.

{{{6*x+x^2=91}}}
{{{x^2+6*x-91=0}}}
The roots are:
{{{x = (-6 +- sqrt( 6^2-4*1*(-91)))/(2*1)}}}
We keep only the positive root since the problem states that the integer is positive.
Therefore 
{{{x=7}}}